Let f(x)=3x^2+4x+4 and let q(h)=f(3+h)−f(3)/h. Then q(0.02)=

Answer 1

q(.02) = f(3.02) - f(3))/.02 = (3(3.02)^2 + 4(3.03) +4 - (3(3)^2 +4(3) +4)))/.02

= (3(9.1204) +12.12 + 4 - 27 -12 -4)/.02

= (27.3612 -27 +.12)/.02

= (.3612 +.12)/.02

= .4812/.02

= 24.06