The length of a rectangle is 13 more than twice its width. If the area of the rectangle is 24 cm 2 , what are the dimensions of the rectangle?

Answer 1

L = 13 +2w

A = 24 cm^2 = Lw = (13+2w)w = 13w +2w^2

2w^2 + 13w -24 = 0

(2w +3)(w-8) = 0

w = 8 cm wide or -3/2 cm

L - 24/8 = 3 cm Long or 24/-3/2 = -16

8 by 3 cm or - 3/2 by -16 cm but ignore the negative solution