How many liters of 10% acid solution must be mixed with a 50% acid solution in order to obtain 25 liters of a 30% solution?

Question

How many liters of 10% acid solution must be mixed with a 50% acid solution in order to obtain 25 liters of a 30% solution?

can you show you get the solution step by step

Answer 1

you probably want the more conventional approach

.10(25-x) + .50(x) = .30(20) solve for x, expand and combine like terms, which is more a far more error prone method

2.5 -.1x +.5x = 6

.4x = 3.5

x = 3.5/.4 = 35/4 = 8.75 liters of 50%

25 -x= 25-8.75 = 16.25 Liters of 10%

check the answers

.10(16.25) + .50(8.75) = 1.625 + 4.375 =6 It works