Find the polynomial with given zeros and point...

Question

write a polynomial with the zeros of: -3, 1, 4 whose graph passes through the point (6, 270)

im so confused so any help would be appreciated! Thank you so much!

Answer 1

Start by writing

f(x) = A [x - (-3)] (x - 1)(x - 4) ⇒

f(x) = A(x + 3)(x - 1)(x - 4)

A is a real nonzero number. Since the point (6,270) is on the curve, set

270 = A(6 + 3)(6 - 1)(6 - 4)

Now solve for A and finish from here.