What is the positive solution to (x-7)x-4)=0

Answer 1

if you mean (x-7)(x-4) =0 there's two positive solutions, 7 and 4

but if you really did mean (x-7)x - 4 = 0

then solve x^2 -7x -4 = 0

x = 7/2 +(1/2)sqr(49 +16) = 3.5 +.5sqr65 = the one & only positive solution

= about 7.53113

by graphing x= 7.53113... x intercept of the parabola

impossible to factor so give up on that method

or there's trial and error method, by Descartes rule of signs there's 1 + zero, and 1 - zero

try integers x=1, y = -10 not 0

x=2,3,4,5 6 or 7, y <0

x=8 y = 64 -56-4 = +4

y changes sign between x=7 and 8, so solution is 7<x<8, closer to 8 which is 7.53113...