find an equation of the line that satisfies the given conditions through (1,-8); parallel to the line x +2y=6

Question

find an equation of the line that satisfies the given conditions through (1,-8); parallel to the line x +2y=6

Answer 1

x+2y=6

2y=-x+6

y= (-1/2)x + 3

slope = -1/2 for this equation or any line parallel to it

for (1,-8) use the point slope formula

y-h=m(x-k) where (h,k) = (1,-8) and m= -1/2

y+8 = (-1/2)(x-1)

multiply by 2

2y+16 = -x+1

2y+x = --15