If you randomly select five peanut M&M’s, compute that probability that at least one of them is green

Answer 1

Typically in a peanut m&m bag there will be six colors: blue, orange, green, yellow, red, and brown. However, you are unable to tell the probability that one will be green without more information. It depends on how many of each colored m&m is in the bag.

But, if you were to input this into a type of equation you would do:

(number of green m&m's ⁄ total number of m&m's)×100= the probability that you will pick a green m&m

Hypothetically lets say you have a bag of 20 m&m's: 3 blue, 2 orange, 4 green, 3 yellow, 2 red, and 6 brown. If you randomly picked 5 m&m's out of the bag you have a 20% chance that one will be green. This is because 4 out of 20 m&m's are green. You then divide 4 by 20 (4⁄20) to get an answer of 0.20. Now to make it into a probability you must multiply it by 100 (0.20×100) resulting in an answer of 20%. Hence there is a 20% probability that you will get pick a green m&m.

*note the probability will change with each m&m as the total amount of m&m's and colors change*

Answer 2

How many other colors are there???????????????????????