how to write an equation of the line that is parallel to y = -3x +1 and passes through the point (4, 2)

Answer 1

how to write an equation of the line that is parallel to y = -3x +1 and passes through the point (4, 2)

SLOPE INTERCEPT FORMULA: Y = MX + B where M is the SLOPE,and

B is the Y-INTERCEPT(where the line crosses the Y axis, and X=0).

Given the STRAIGHT LINE aka LINEar EQUATION Y = -3X + 1, we know

the SLOPE is -3.

Since the two lines are PARALLEL, then their SLOPES ARE THE SAME, -3.

So, now we have Y = -3X + B

But, we need to solve for B, which is the Y-INTERCEPT by plugging in a value for X, and a value for Y, using the coordinate (4,2). So, X=4 and Y=2.

2 = -3(4) + B

2 = -12 + B

14 = B

ANSWER: Y = -3X + 14

Hope this helps you Corinne.