The quotient rule is:
f(x) = 4
g(x) = ln(x)
f '(x) = 0
g'(x) = 1/x
g(x)2 = (ln(x))2
So:
y' = [0•ln(x) - (1/x)(4)]/(ln(x))2
y' = (-4/x)/(ln(x))2
y' = -4/[x(ln(x))2]
Amy Q.
asked 09/05/20differentiate using the quotient rule. Please include steps and formulas I am struggling to understand
The quotient rule is:
f(x) = 4
g(x) = ln(x)
f '(x) = 0
g'(x) = 1/x
g(x)2 = (ln(x))2
So:
y' = [0•ln(x) - (1/x)(4)]/(ln(x))2
y' = (-4/x)/(ln(x))2
y' = -4/[x(ln(x))2]
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