Pre calc- h(x) = f(g(x))

Question

Hey I need help on f(g(x)) where h (x) = 4^3 (square root ) x^2-3x+2 (square root ends) minus 5

Answer 1

h(x) = 64sqrt(x² 3x + 2) - 5.

We have to decompuse h(x) using f(x) and g(x)

Let say f(x) = 64sqrt(x) - 5 and g(x) = x² - 3x + 2.

Then f(g(x)) = 64sqrt(g(x)) - 5 = 64sqrt(x² - 3x + 2) - 5 = h(x)