If f(x) = x^2-3x and g (x) = sqrt (x) -1 then f(g(x)) = ?

Question

The x is the only one that have a square root. Thank you I need help lol

Answer 1

f(x) = x² - 3x and g(x) = √x - 1

f(g(x)) = f(√x - 1) = (√x - 1)² - 3(√x - 1) = x - 2√x + 1 - 3√x + 3 = x - 5√x + 4

Answer 2

If f(x) = x^2-3x and g (x) = sqrt (x) -1

then f(g(x)) = 

(sqrt(x) - 1 )^2 - 3(sqrt(x) - 1)

x - 2sqrt(x) + 1 - 3sqrt(x) - 3

x -5sqrt(x) - 2