Write and solve a system of linear equation to find the length and the width of the rectangle

Question

The perimeter of a rectangle is 34 centimeter. The length is two more thaN twice the width.

Answer 1

P=2w+2l

l=2w+2  [The question says the length is 2 more then twice the width]

w=w

 

Now, substitute 2w+2 for l in the original equation and solve for w.

 

34=2w+2(2w+2)

34=2w+4w+4

34=6w+4

30=6w

5=w

 

Therefore, the width is 5 and the length is 2(5)+2, or 12.

 

I hope that helps.