Ryan S. answered 12/13/13
Tutor
4.8
(10)
Mathematics and Statistics
Let x be the amount invested at 6% and y be the amount invested at 10%.
One equation states that the total invested is $12,000
x + y = 12,000
Another equation states that the interest earned is $1040
0.06x + 0.10y = 1040
Multiplying the second equation by -10 gives
-0.6x - y = -10,400
Adding this to the first equation eliminates y and gives
0.4x = 1600
x = 4000
Substituting 4000 for x into the first equation gives
4000 + y = 12,000
y = 8000