
Philip P. answered 04/13/14
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x+3y=11 and 2x-y=1
There are two standard ways to solve this pair of equations, substitution and linear combination.
Substitution:
x+3y=11
2x-y=1
Rewrite the second equation solving for x:
2x = y + 1
x = (1/2)y + (1/2)
Substitute (1/2)y + (1/2) for x in the first equation:
x+3y=11
(1/2)y + (1/2) +3y = 11
(7/2)y = 21/2
y = 3
Find x: x = (1/2)y + (1/2) = (1/2)(3) + (1/2) = 3/2 + 1/2 = 2
x=2
Linear Combination:
x+3y=11
2x-y=1
2x-y=1
Multiply the first equation by -2
-2x -6y = -22
Now add it to the second equation to eliminate the x terms:
-2x - 6y = -22
2x - y = 1
------------------
0 - 7y = -21
y = 3
Find x: x = 11 - 3y = 11 - (3)(3) = 2
x=2