Ta C.

asked • 08/19/20# Write the point (3, pi/6) with the following conditions: a. r < 0, theta > 0 b. r > 0, theta < 0 c. r > 0, theta > 0

Write the point (3, pi/6) with the following conditions:

a. r < 0, theta > 0

b. r > 0, theta < 0

c. r > 0, theta > 0

## 1 Expert Answer

Mike D. answered • 08/19/20

Effective, patient, experienced math tutor who can help you succeed

Ta

(c) is obvious - r=3 theta = pi/6

(b) r = 3. For a negative theta we go clockwise starting from the x axis , as a whole revolution is 2 pi, we need to go 2 pi - pi / 6. So r = 3, theta = - (2 pi - pi /6)

(a) r<0. This means theta = pi + pi/6, and r = -3. BECAUSE -3 units down the line theta = pi + pi/6 is the same as +3 units up the line theta = pi/6

Mike

## Still looking for help? Get the right answer, fast.

Get a free answer to a quick problem.

Most questions answered within 4 hours.

#### OR

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.

Joseph C.

I find this question confusing, because the point (3,pi/6) is already implies that r>0 and theta>0. This is because the (3,pi/6) -> (r,pi/6). In fact, in polar coordinates r<0 is not a valid value.08/19/20