Inactive Tutor answered 07/29/20
Tutor
New to Wyzant
1) sin(-π/3) = - sinπ/3 = √3/2; cos(-π/3) = cosπ/3 = 1/2
2) sin(-11π/6 = sin(-11π/6 + 2π)= sinπ/6 = 1/2; cos(- 11π/6) = cos(-11π/6+ 2π) = cosπ/6 =√3/2
Inactive Tutor answered 07/29/20
1) sin(-π/3) = - sinπ/3 = √3/2; cos(-π/3) = cosπ/3 = 1/2
2) sin(-11π/6 = sin(-11π/6 + 2π)= sinπ/6 = 1/2; cos(- 11π/6) = cos(-11π/6+ 2π) = cosπ/6 =√3/2
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