x = 0 x = 3 + 5i (x = 3 - 5i)
This polynomial function does have a conjugate pair.
x = 3 ± 5i
x - 3 = ± 5i
(x - 3)2 = -25
x2 - 6x + 9 = -25
x2 - 6x + 34 = 0
x(x2 - 6x + 34) = x3 - 6x2 + 34x
P(x) = x3 - 6x2 + 34x
Jade F.
asked 07/28/20Find a cubic polynomial in standard form with real coefficients, having the given zeros.
0 and 3+5i
x = 0 x = 3 + 5i (x = 3 - 5i)
This polynomial function does have a conjugate pair.
x = 3 ± 5i
x - 3 = ± 5i
(x - 3)2 = -25
x2 - 6x + 9 = -25
x2 - 6x + 34 = 0
x(x2 - 6x + 34) = x3 - 6x2 + 34x
P(x) = x3 - 6x2 + 34x
Ross C. answered 07/28/20
Licensed math educator with 8 years of in-classroom experience!
Hi Jade,
Here's one way that you can approach this problem. Hopefully it helps!
Ross
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