x = 3 + 2i (x = 3 - 2i) x = −1 x = 2
The polynomial function does come in conjugate pairs. Find the factors for each zero.
x - 3 = ± 2i x = -1 x = 2
(x - 3)2 = -4 x + 1 = 0 x - 2 = 0
x2 - 6x + 9 = -4
x2 - 6x + 13 = 0
(x + 1)(x - 2)(x2 - 6x + 13) = (x2 - 2x + x - 2)(x2 - 6x + 13)
= (x2 - x - 2)(x2 - 6x + 13)
= x4 - 6x3 + 13x2 - x3 + 6x2 - 13x - 2x2 + 12x - 26
= x4 - 7x3 + 17x2 - x - 26
P(x) = x4 - 7x3 + 17x2 - x - 26