A two-acre building lot is five times as long as it is wide. What are its dimensions? [Note: 1 acre = 43,560 ft^2.]

Question

A two-acre building lot is five times as long as it is wide. What are its dimensions? [Note: 1 acre = 43,560 ft^2.]

 

I need to find the length and width 

Answer 1

Assuming the lot is rectangular, the area of a rectangle is length * width. Since we know the length is five times the width, i.e. length = 5 * width, and we know the area is 2 * acres = 2 * 43560 ft², we can use substitution to get the formula 87120 = (5 * width) * width.

 

87120 = 5 * width * width         (rewrite width * width as width²)

87120 = 5 * width²                     (divide both sides by 5)

17424 = width²                           (take the square root of both sides)

132 = width

 

And since the length is five times the width, the length = 5 * 132 = 660.

Answer 2

First, you need to find the area of your lot. Then you can use Area = length * width to solve.

 

Remember, you know the lot is five times as long as it is wide, so length = 5*width.

 

Your new area equation will look something like this: Area = (5*width) * width when you substitute in the former equation.

 

From here you should be able to solve to find your length and width.

Answer 3

draw a picture.

 

2 acres = 87,120 ft²

 

width = w

length = 5w

5w*w=87120

5w²=87120

w²=17424

w= 132 ft  therefore length = 660 ft.