g(g(x))' = g'(g(x))g'(x)
Thus, G'(1) = g'(g(1))g'(1)
g(1) = 2
g'(1) = 6
g'(2) = 7
Thus, g'(g(1))g'(1) = g'(2)g'(1) = 7 * 6 = 42
Qaeeref F.
asked • 06/18/20PLEAE ANSWER ASAP
Let f and g be the functions in the table below.
| xf(x)g(x)f '(x)g'(x) | ||||
| 1 | 3 | 2 | 4 | 6 |
| 2 | 1 | 3 | 5 | 7 |
| 3 | 2 | 1 | 7 | 9 |
(b) If G(x) = g(g(x)), find G'(1).
G'(1) =
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Qaeeref F.
Thank you very much!, I was confused on this section.06/18/20