Tom K. answered 06/18/20
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g(g(x))' = g'(g(x))g'(x)
Thus, G'(1) = g'(g(1))g'(1)
g(1) = 2
g'(1) = 6
g'(2) = 7
Thus, g'(g(1))g'(1) = g'(2)g'(1) = 7 * 6 = 42
Qaeeref F.
Thank you very much!, I was confused on this section.06/18/20