
Russ P. answered 02/08/15
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Patient MIT Grad For Math and Science Tutoring
Macy,
Let x = length of shortest leg of right triangle (in cm)
(x + 2) = length of longer leg (in cm)
(x + 4) = length of hypotenuse (in cm)
Now for a right triangle use the c2 = a2 + b2 formula that relates the 3 sides of the triangle.
Then
(x + 4)2 = x2 + (x + 2)2 . Expand this
(x2 + 8x + 16) = x2 + (x2 + 4x + 4) , then combine terms on the right side
0 = x2 - 4x - 12 , We can use the quadratic formula to solve this, but it's simpler in this case to factor it.
0 = (x - 6) ( x + 2) , for the product of the 2 factors to be zero, one or both have to be zero
So first try (x + 2) = 0 implies x = -2 cm , but triangle side can't be negative, so discard this solutionn
next try (x - 6) = 0 implies x = 6 cm.
So your right triangle has sides : 6 cm , 8 cm and 10 cm for the hypotenuse.
Check: (10)2 =? (6)2 + (8)2 ,
100 = 36 + 64 = 100 so it checks as the correct unique solution.