Arturo O. answered 06/07/20
Experienced Physics Teacher for Physics Tutoring
P = 2(L + W)
W = L - 4 (in inches)
P = 32 inches
32 = 2[L + (L - 4)]
Solve for L, then get L - 4. You should be able to finish from here. The answers will be in inches.
Maria G.
asked 06/07/20The perimeter of a rectangle is 32 inches. If the width is 4 inches less than the length, find the dimensions of the rectangle
Arturo O. answered 06/07/20
Experienced Physics Teacher for Physics Tutoring
P = 2(L + W)
W = L - 4 (in inches)
P = 32 inches
32 = 2[L + (L - 4)]
Solve for L, then get L - 4. You should be able to finish from here. The answers will be in inches.
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