What's the probability of bowler takes no wicket in below question?

Question

On an average, a bowler takes a wicket every 8 overs. If bowler bowls 10 overs, what is the probability that the bowler succeeds in taking no wicket in those overs.

Answer 1

There's a 1/8 chance that he takes a wicket with each over. So the probability of him NOT taking a wicket with an over is 7/8. Because each over is an independent event, the probability of him taking no wickets in 10 overs will be (7/8)^10 = 282475249/1073741824.