Edward C. answered 05/14/20
Caltech Grad for math tutoring: Algebra through Calculus
Hi Saeed,
These are introductory examples of integration by substitution. Try looking at the integrals to see if you can find both a function f(x) and its derivative f'(x) present in the integrand. If so, making the substitution u = f(x) and du = f'(x)dx may prove fruitful.
For example, suppose you were trying to find ∫(x6 + 1)4(6x5)dx. Since 6x5 is the derivative of x6 + 1, make the substitution u = x6 + 1, du = 6x5dx to get ∫u4du, which integrates easily to u5/5 + C by the Power Rule. Substituting back to get the answer in terms of x gives the result as F(x) = (x6 + 1)5/5 + C, and the derivative is easily checked to be F'(x) = (x6 + 1)4(6x5) using the Chain Rule.