a numbers is 9 times a first number. a third number 100 more than the first number is the sum of the the numbers is 848 find the numbers

Question

a numbers is 9 times a first number. a third number 100 more than the first number is the sum of the the numbers is 848 find the numbers

Answer 1

n = first number

9n = second number

n + 100 = third number

n + 9n + (n + 100) = 848

Can you solve for n and finish from here?