Inactive Tutor answered 05/14/20
This is matrix [1,1,0,0], becau(1 ,-1, -1, 1) se equation [1,1,0,0] · [x,y,z,t]T = [0] give us plane x + y = 0 in R2 and points (1 ,-1, -1, 1) and (1, -1, 1, 1) inthis plane, because x + y =x + y + 0·z+0·t = 0
Alex K.
asked 05/12/20How to Construct a matrix to project vectors in 4-dimensional space to a 2-dimensional plane that lies in the space and passes through the origin and the points (1 ,-1, -1, 1) and (1, -1, 1, 1).
Inactive Tutor answered 05/14/20
This is matrix [1,1,0,0], becau(1 ,-1, -1, 1) se equation [1,1,0,0] · [x,y,z,t]T = [0] give us plane x + y = 0 in R2 and points (1 ,-1, -1, 1) and (1, -1, 1, 1) inthis plane, because x + y =x + y + 0·z+0·t = 0
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