How to solve problem

Question

Bob had 20 red apples and 28 yellow apples. He ate two red and 3 yellow apples a day until he had 6 red left. How many yellow apples are left?

Answer 1

There are 7 yellow apples left.

Since Bob ate 2 red apples each day, ending up with 6 left at the end, that means he ate red apples for 7 days. 7x2=14; 20-14=6.

Therefore, since Bob ate 3 yellow apples each day for 7 days: 7x3=21. 28-21=7

I hope this helps!

Answer 2

Bob had 20 red apples and 28 yellow apples. He ate two red and 3 yellow apples a day until he had 6 red left. How many yellow apples are left?

20 red - ? = 6 red left

? = 14 red apples he ate

He ate 2 red apples a day.

14/2 = 7 days

He ate 3 yellow apples a day for 7 days.

He ate 21 yellow apples.

28 yellow apples - 21 yellow apples = 7 yellow apples left over