Solve for x (algebra)

Question

m = (1/3) (xy)²

I'm solving for x

m = 1/3(x²y²)

m = x²y²/3

3m = x²y²

3m/y² = x²

±√3m/y² = x >>>> or is it ±√3m/y = x, this is my problem

±3^1/2m^1/2/(y²)^1/2 = x

±3^1/2m^1/2/y = x

±√3m/y = x

If this is the correct answer, how is the next step?

Answer 1

m = (1/3)(xy)²

3m = x²y²

x² = 3m / y²

x = √(3m) / y