Don has 10% ethanol gasoline and 50% ethanol gasoline. If a customer wants 800 liters of 25% ethanol gasoline, how many liters of 10% and 50% ethanol must be mixed?

Answer 1

.50x + .10(800-x)= 800(.25= 200

.40x =120

x = 120/.4 = 300 Liters of 50%

500 Liters of 10%