Velocity question

Question

A ball is thrown vertically upward from the ground with an initial velocity of 102 ft/sec. Use h=-16^2+v+h. Determine when the ball will reach it's maximum height in seconds, and what the maximum height will be

Answer 1

h' = -32t + 102 = 0, t = 102/32 = 51/16 = 3 3/16 seconds to reach max

maximum height = -16(51/16)^2 + 102(51/16) feet high = 162.5626 ft