f(x)=3sin(8x)sin−1(4x), find f′(x). f′(x) = ?

Question

f(x)=3sin(8x)sin−1(4x), find f′(x). ... f′(x) = ? ( derivative )

Answer 1

To find the derivative of 3sin(8x)sin^-1(4x), we need to use the product rule. We can leave the 3 out front and then just take the derivative of sin(8x)sin^-1(4x). This will give us 3 [ 8cos(8x)sin^-1(4x) + sin(8x)(4/√(1-16x²)) ] = 24cos(8x)sin^-1(4x) + 12sin(8x) / √(1-16x²)