Matthew S. answered 04/04/20
PhD in Mathematics with extensive experience teaching Calculus
Consider a right triangle with sides
r(t):= distance between runner & 3rd base at time t and
s(t):= distance 3rd base to home plate. Note this is constant.
h(t):= distance between runner and home plate (h for hypotenuse). We want dh/dt
r2(t)+s2(t) = h2(t)
Differentiate both sides with respect to t:
2r(t)*dr/dt + 2s(t)*ds/dt = 2h(t)*dh/dt
Cancel the 2's and notice that ds/dt = 0.
When r(t) = 25', we know that h(t) = √252 + 902 ≈ 93.4'
We're also told that, at the same moment in time, dr/dt = -28 ft/sec (distance to 3rd base is decreasing, hence the negative sign)
Therefore 25 * (-28) = 93.4*dh/dt and dh/dt = 25*(-28)/93.4