
Katherine E. answered 04/03/20
Outgoing & Patient Special Education Teacher with M.Ed
Hi Jose!
When solving this problem, I was looking for the least common multiple, or the smallest number that can be divided by both 4 and 3. The least common multiple for 3 and 4 is 12. I started by multiplying 4 x 3=12. Next, I considered all the numbers smaller than 12 that are divisible by both 3 and 4. There aren't any.
If 12 is my least common multiple, I need to divide 12 by both 3 (number of pens in a package) and 4 (number of pencils in a package) to determine the number of packs for each school supply.
Number of packages of pencils--
12÷3= 4
So, I need 4 packages of pencils.
Number of packages of pens--
12÷4=3
So, I need 3 packages of pens.
You would need to put 3 packages of pencils and 4 packages of pens in a bag for their to be the same amount of each item. There will be 12 of each item.