You have a triangle with two equal sides a Perimeter of 80 cm with the third side 8 cm longer than the other side.
P =s1 + s2 + s3
Let s1 = s2 = s for the measure each of the two equal sides
Let s3 = s + 8 for the third side
80 = s + s + s + 8
80 = 3s + 8
Subtract 8 from both sides to isolate the variable
80 - 8 = 3s
72 = 3s
Divide both sides by 3 to solve for s
24 = s
s1 = 24
s2 = 24
s3 = 24 + 8 = 32