Irene R. answered 03/30/20
Senior Mechanical Engineer with 13+ years of Teaching Experience
Let's use the variable s to represent the cost on one senior ticket and the variable c represent the cost of one child ticket.
Now we can write two equations based on the info given in the problem:
3s + 1c = 38
3s + 2c = 52
These equations can be solved using elimination. Multiply the first equation by -1:
3s + 1c = 38 becomes -3s - 1c = -38
3s + 2c = 52
Now combine the two equations to find the value of c:
-3s - 1c = -38
3s + 2c = 52
1c = 14
The cost of one child ticket is $14
Use either equation to find the value of s. Using the second equation, substitute 14 for c:
3s + 2c = 52
3s + 2•14 = 52
3s + 28 = 52
3s + 28 - 28 = 52 - 28
3s = 24
3s/3 = 24/3
s = 8
The cost of one senior ticket is $8.