First day:
distance travelled = 325 km
time taken = x hours
speed = 325/x km/h
Second day:
distance travelled = 58 km
time taken = (6 - x) hours
speed = (325/x - 7) km/h = 58/(6 - x)
Solve the equation (325/x) - 7 = 58/(6 - x)
Multiply the entire equation by x(6 - x)
325(6 - x) - 7(x)(6 - x) = 58x
(1950 - 325x) - (42x - 7x2) = 58x
Rearrange it:
7x2 - 425x + 1950 = 0
Solving it by quadratic formula:
x = 390/7, 5
Since 390/7 > 6, which is not a feasible answer as time can never be smaller than 0
Thus, x = 5 hours
Joey S.
How fast did he travel the first day?03/27/20