x * 0.08 + (6000 - x) * 0.10 = 522

Answers would be x and (6000 - x)

Ana R.

asked • 03/24/20julio invests $6000 in two different accounts. The first account paid 8 %, the second account paid 10 % in interest. At the end of the first year he had earned $522 in interest. How much was in each account?

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x * 0.08 + (6000 - x) * 0.10 = 522

Answers would be x and (6000 - x)

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