The length of a rectangle is twice its width. If the area of the rectangle is 50m^2 , find its perimeter.

Answer 1

Let W = Width

Let 2W = Length since the length is twice as long as the width

Area = 50 square meters

Area = Length x Width = (2W) (W)

(2W) (W) = 50

(W) (W) = 25 Dividing both sides by 2.

W^2 = 25

W = 5 Taking the square root of both sides.

So, the WIDTH of the rectangle is 5 meters.

The LENGTH of the rectangle is 2W = (2)(5) = 10 meters

The PERIMETER = 2L + 2W = (2)(10) + (2)(5) = 20 + 10 = 30 METERS

CHECKING:

Area = LW = (5)(10) = 50 square meters

Perimeter = 10 + 5 + 10 + 5 = 15 + 15 = 30 meters

Hope this helped Gracie.