Differentiate y = (r^2 − 6r)e^r

Answer 1

use the product rule y'(r) = u'(r)v(r)+v'(r) u(r) where u(r) = r^2-6r, v(r) = e^r. u'(r) = 2r -6 and v'(r) = e^r

y'(r) = e^r(2r-6)e^r + e^r (r^2-6r) = e^r(r^2-4r-6)