Raymond B. answered 01/12/26
Tutor
5
(2)
Math, microeconomics or criminal justice
L = 5w - 26cm
A = Lw = 63 = w(5w -26) = 5w^2 -26w
5w^2 -26w -63 =0
(5w + 9)(w -7) = 0
w = 7 cm
L - 9 cm
Sabrena B.
asked 02/19/20The length of a rectangle is 26 centimeters less than five times it’s width. It’s area is 63 square centimeters. Find the dimensions of the rectangle
Raymond B. answered 01/12/26
Math, microeconomics or criminal justice
L = 5w - 26cm
A = Lw = 63 = w(5w -26) = 5w^2 -26w
5w^2 -26w -63 =0
(5w + 9)(w -7) = 0
w = 7 cm
L - 9 cm
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