Find a Formula for the quadratic function whose graph has the given properties. A vertex (8,4) and a y-intercept of y=-8. y=

Answer 1

Quadratic Function Vertex Form: y = a(x-k)^2 + h, where vertex (k, h)

Given: vertex (8, 4), y-intercept point (0, -8)

meaning: k=8, h=4; and while y=-8, x=0

substitute k, h, x, y value in equation: -8 = a(0 - 8)^2 + 4

solve for a: a= -3/16

Quadratic Function is: y=-3/16(x-8)^2 + 4