Let the function f be defined by y = f(x), where x and f(x) are real numbers. Find f(4), f(−5), f(k), and f(k2 − 1). f(x) = 5x + 7 f(4) = f(−5) = f(k) = f(k2 − 1) =

Answer 1

f(x) = 5x+7

f(4) = 5*4+7 = 20+7 = 27

f(-5) = 5*(-5)+7 = -25 + 7 = -18

f(k) = 5k+7

f(k^2-1) = 5(k^2-1) + 7 = 5k^2 - 5 + 7 = 5k^2+2