The talent show committee sold a total of 530tickets in advance. Student tickets cost $3 each and adults tickets cost $4 each. If the total receipts were $1740, how many of each type ticket were sold?

Answer 1

Total tickets = 530

Students $3

Adults $4

Total $1740

Use x as the amount of tickets sold to students and y as the amount of tickets sold to adults.

Therefore, we can now form the equations below:

3x + 4y = 1740 equation 1

x + y = 530 equation 2

Multiply equation 2 by 3 to equal the x in equation 1

3x + 3y = 1590 equation 3

Now subtract equation 3 from 1

y = 150

Sub. y into above equation.

x + y = 530

x + 150 = 530

x = 380

150 adult

380 student tickets

Answer 2

Let the number of student tickets = "s". Let the number of adult tickets = "a"

Then a + s = 530

Also, when considering the revenue taken,.3s + 4a = 1740

You can solve systems of equations in multiple ways, but in this case, let's solve the first equation for s. s = 530 - a

Now we can plug "530 - a" into the second equation wherever we see "s". So:

3(530 - a) + 4a = 1740

1590 - 3a + 4a = 1740

a = 150

Give a = 150, we can plug this into the original equation a + s = 530 to get 150 + s = 530 or s = 380

So the number of student tickets sold is 380 an the number of adult tickets sold is 150

Answer 3

A+S = 530

3S + 4A = 1740

3S+ 4(530 - S) = 1740

3S + 2120 - 4S = 1740

-S + 2120 = 1740

-S = 1740 - 2120

-S = -380

S = 380

A= 530 - 380 = 150

380*3 + 4*150 = 1140 + 600 = 1740

380 student tix

150 adult tix