lim h?0 h2 + h 6h2 + 3h

Question

Calculate the limit algebraically.

 

If the limit does not exist, say why. (If the limit does exist, so state.)

Answer 1

(h² + h)/(6h² + 3h) = [h(h + 1)]/[h(6h + 3)]

 

                                     = (h + 1)/(6h + 3)

 

As h→0, (h + 1)/(6h + 3) → (0 + 1)/(6(0) + 3) = 1/3

Answer 2

As written, if h goes to 0, you have nothing left.  I'm wondering if you missed a division sign or something?  If not, your limit is just 0.