If f (x) =√ 2 x − 3, and f(a) = 5, then a =?

Answer 1

f(x) = (sqr2)x -3? (sqr2x)-3? or sqr(2x-3)??

3 different problems with 3 different solutions

f(a)=5 = (sqr2)x-3, then x = 8/sqr2 = 4sqr2 = a

f(a) = 5 = (sqr2x) -3, then sqr2x = 8, 2x =64, x = 32 = a

f (a)=5 = sqr(2x-3), then 25 = 2x-3, 2x = 28, x = 14 = a