
Yefim S. answered 10/06/24
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Rn = ∑k=1n[-(4k/n)2/3 + 7]·4/n = 4/n[- 16n(n + 1)(2n + 1)/(18n2) + 7n] = - 32(n + 1)(2n + 1)/9n2 + 28
lmRn as n→∞∞ = - 64/9 + 28 = 188/9 = ∫04(- x2/3 + 7)dx