n = 3 3 and 5i are zeros f(1) = -52 Find the expanded and simplified polynomial

Answer 1

x = 5i

x^2 = -25

x^2 + 25 is one factor

x-33 another

a another

a(x-33)(x^2+25) = -52 when x =1

a(-2)(26) = -52

a = -52/(-2)(-26) = 1

f(x) = (x-33)(x^2 +25)

f(x) = x^3 -33x^2+25x - 825