Solve for V in the equation h=-16t^2+vt+k

Question

h=-16t^2+vt+k

 

The equation above gives the height h, in feet, of a ball t seconds after it is thrown straight up with an i speed of v feet per second from a height of k feet.

The equation above gives the height h, in feet, of a ball t seconds after it is thrown straight up with an initial speed of v feet per second from a height of k feet. Which of the following gives v in terms of h, t, and k?

And this is the question because it doesn't fit up on the question area.

Here are the option and plz can you show the work?

A. v=h+k-16t

B. v=h-k+16/ t

C. v=h+k/t-16t

D. v=h-k/t+16t

Answer 1

h=-16t²+vt+k Add 16t² to both sides

h+16t²=-16t²+vt+k+16t² Simplify

h+16t²=vt+k Subtract k from both sides

h+16t²-k=vt+k-k Simplify

h+16t²-k=vt Divide both sides by t

h/t+16t²/t-k/t=vt/t Simplify

(h-k)/t+16t = v

D (Parenthesis are missing in all these answers - it is important to show parenthesis so both terms divide by t)