Raymond B. answered 08/06/25
Math, microeconomics or criminal justice
5w+ 2L = 26
15w-3L = 6
15w-6L = 3(26)
9L = 3(26)-6=72
L = 72/9= 8
w = 2
Sean T.
asked 11/08/19The sum of 5 times the width of a rectangle and twice it’s length is 26 units. The difference of 15 times the width and three times the length is 6 units. Write and solve a system of equations to find the length and width of the rectangle.
Raymond B. answered 08/06/25
Math, microeconomics or criminal justice
5w+ 2L = 26
15w-3L = 6
15w-6L = 3(26)
9L = 3(26)-6=72
L = 72/9= 8
w = 2
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