Raymond B. answered 01/13/26
Tutor
5
(2)
Math, microeconomics or criminal justice
101^a + 103^b = 10403^c = (101(103))^c = 101^c(103)^c
c = a/(1+log103 to the base 101) + b/(1+ log101 to the base 103)
c = a(1+ln103/ln101) + b/(1+ ln101/ln103)
=